Let #f(x)=2x^2+2#, how do you find f(.1)?
1 Answer
Substitute
Explanation:
#2 (0.1)^2 + 2#
#2 (0.01) + 2#
#0.02 + 2#
#2.02#
Therefore,
#f(0.1) = 2.02#
Substitute
#2 (0.1)^2 + 2#
#2 (0.01) + 2#
#0.02 + 2#
#2.02#
Therefore,
#f(0.1) = 2.02#