Question

Question #64b2f

Answer 1

`x=1.3083+-0.6324i`

Explanation:

To solve for `x` in the quadratic equation

`y=-0.7428x^2+1.9437x-1.569`

Use the quadratic formula, which solves for `x` in the quadratic equation

`y=ax^2+bx+c`

where

`x=(-b+-sqrt(b^2-4ac))/(2a)`

In the given quadratic, we see that

`{(a=-0.7428),(b=1.9437),(c=-1.569):}`

Thus,

`x=(-1.9437+-sqrt(1.9437^2-4(-0.7428)(-1.569)))/(2(-0.7428))`

`x=(-1.9437+-sqrt(-0.8838))/(-1.4856)`

Bring the negative out as `i`. Take the square root of `0.8838`.

`x=(-1.9437)/(-1.4865)+-0.9401/(-1.4856)i`

`x=1.3083+-0.6324i`