Question

Question #c7e58

Answer 1

See the Proof in Explanation section.

Explanation:

`cot^2v-cos^2v=cos^2v/sin^2v-cos^2v=cos^2v(1/sin^2v -1)`

`=cos^2v(csc^2v-1)=cos^2vcot^2v`. Thus,

`cot^2v-cos^2v=cot^2vcos^2v`

`:. (cotv-cosv)(cotv+cosv)=(cotvcosv)(cotvcosv)`.

`:. (cotv-cosv)/(cotvcosv)=(cotvcosv)/(cotv+cosv)`

Hence, the Proof.