Question

Question #30af4

Answer 1

`LHS=sinx/(1-cosx)`

`=(sinx(1+cosx))/((1-cosx)(1+cosx))`

`=(sinx(1+cosx))/(1-cos^2x)`

`=(sinx(1+cosx))/sin^2x`

`=(1+cosx)/sinx`

`=1/sinx+cosx/sinx`

`=cscx+cotx=RHS`

Proved that it is an identity,not an equation.