Question

Question #2f605

Answer 1

`x=pi/4 +pin, x= -pi/6 +pin`

Explanation:

`cos (2x-pi/6)=1/2`
`2x-pi/6 = cos^-1 (1/2)`
`2x-pi/6 = +- pi/3 + 2pin`
`2x=pi/6 +- pi/3 + 2pin`
`2x=pi/2+2pin, 2x=-pi/3+2pin`
`x=pi/4 +pin, x= -pi/6 +pin`