Question

Question #5cb57

Answer 1

The weight of 100cm uniform bar will at the center of gravity i.e. at the middle point `G` of the bar.

A support is at the point X on the bar and this point is at a distance of 23 cm from one end A from which an unknown weight `Wkg` is hanged to balance the system.

Here `XA=23cm and XG=(50-23)=27cm`

Considering the moments of the weight `Wkg` and weight of the bar about X we can write

`"weight of bar"xxXG=WxxXA`

`=>17.2xx27=Wxxxx23`

`=>W=20.2cm`