Question

Question #53a86

Answer 1

Given

`cosq=-sinq`

`=>cosq=cos((3pi)/2-q)`

`=>q=(3pi)/2-q`

`=>2q=(3pi)/2`

`=>q=(3pi)/4`

`=>sinq=sin((3pi)/4)=sin(pi-pi/4)`

`=>sinq=sin(pi/4)=1/sqrt2`

Now `sin^2q=(1/sqrt2)^2=1/2=0.5`