Question #a9af4

1 Answer
Jan 15, 2017

Well, you can recall a basic property of integrals, the integrals of a constant and #sinx#, and the portion of the Fundamental Theorem of Calculus about evaluation of definite integrals:

  • The integral of a sum is the sum of the integrals: #int f(x) + g(x)dx = int f(x)dx + int g(x)dx#.
  • #int Cdx = Cx#, plus some integration constant if for an indefinite integral.
  • #int sinxdx = -cosx#, plus some integration constant if for an indefinite integral.
  • For definite integrals, if #F(x)# is the antiderivative, then #int_a^b f(x)dx = |[F(x)]|_(a)^(b) = F(b) - F(a)#.

So, simplify this and evaluate:

#color(blue)(int_(0)^(pi) 2 + sinxdx)#

#= int_(0)^(pi) 2dx + int_(0)^(pi) sinxdx#

#= 2|[x]|_(0)^(pi) + |[-cosx]|_(0)^(pi)#

#= 2(pi - 0) + [(-cospi) - (-cos0)]#

#= 2pi + [-(-1) - (-1)]#

#= 2pi + 1 + 1#

#= color(blue)(2pi + 2)#