Question

Question #0fe54

Answer 1

The answer is `=2`

Explanation:

If `cotx=5/12`

`tanx=12/5`

`cos^2x+sin^2x=1`

Dividing by `cos^2x`

`1+tan^2x=sec^2x`

`sec^2x=1+12^2/5^2=1+144/25=169/25`

`secx=13/5`

`secx=1/cosx`

`cosx=5/13`

`sinx=sqrt(1-cos^2x)=sqrt(1-25/169)`

`=sqrt144/169=12/13`

`cscx=1/sinx=13/12`

And finally,

`sinx+cscx=12/13+13/12=2`