Question

Solve the equation `sinxcosx=0`?

Answer 1

`x=(npi)/2`, where `n` is an integer.

Explanation:

`sinxcosx=0`

i.e. `2sinxcosx=0` or `sin2x=0`

Hence `2x=npi`, where `n` is an integer.

Hence, `x=(npi)/2`, where `n` is an integer.