Question

Question #1f25e

Answer 1

`2cos^2(x) - 2sin^2(x)=1`

`=>2(cos^2(x) - sin^2(x))=1`

`=>cos2x=1/2=cos(pi/3)`

`=>2x=2npi±pi/3`

`=>x=npi±pi/6," where "n in ZZ`