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Question #9b3b0

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Feb 12, 2017

#2sin3x=sqrt3#

#=>sin3x=sqrt3/2=sin(pi/3)#

#=>3x=npi+(-1)^n(pi/3)" where " n in ZZ#

#=>x=(npi)/3+(-1)^n(pi/9)" where " n in ZZ#

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