Question

Question #c26e4

Answer 1

Area of the square =484 `cm^2`

So each of its sides will be `a= 1/4sqrt"area"=22cm`

So its perimeter `=4xx22==88cm`

The circle formed by bending the same wire will have same perimeter `88cm`. If the circle has got radius `r` then

`2pir=88`

`=>r=88/(2pi)=(88xx7)/(2xx22)=14 cm`

So the area enclosed by the circle `=pir^2=22/7xx14^2=616cm^2`