Question

If `19*mol` of `H_2(g)` react with stoichiometric `N_2(g)`, what molar quantity of ammonia results?

Answer 1

A bit under `13*mol` of ammonia..........

Explanation:

You have the stoichiometric equation........

`N_2(g) + 3H_2(g) stackrel("catalysis")rarr2NH_3(g)`

And clearly, if `19*mol` dihydrogen react completely (which is NOT an altogether probable outcome) then by the stoichiometry we get `19/3xx2*mol=12.7*mol` with respect to ammonia, `NH_3`.......

What is the significance of this ammonia synthesis? Do you think that this reaction is widely performed?