Question

How do we solve the equation `2sinx+sinxcosx=0`?

Answer 1

`x={0,pi,2pi}`

Explanation:

`2sinx+sinxcosx=0` can be written as

`sinx(2+cosx)=0`

As range for `cosx` is `[-1,1]`, `2+cosx >0` and dividing both sides by `2+cosx`, we get

`sinx=0` and in the domain `0 <=x <= 2pi`

`x={0,pi,2pi}`