Question

Question #2a998

Answer 1

`sin x = 2/3`
`cos^2 x = 1 - sin^2 x = 1 - 4/9 = 5/9` -->
`cos x = - sqrt5/3` (because cos x < 0)
`tan x = sin/(cos) = (2/3)(-3/sqrt5) = - 2/sqrt5 = - (2sqrt5)/5`
`cot x = 1/(tan) = - sqrt5/2`
`sec x = 1/(cos) = - 3/sqrt5 = - (3sqrt5)/5`
`csc x = 1/(sin) = 3/2`