Question

Question #63b1d

Answer 1

`LHS=(csc θ + sec θ) / (1+ tanθ)`

`=(1/sintheta + 1/costheta) / (1+sintheta/costheta)`

`=((sintheta +costheta)/(sinthetacostheta)) / ((costheta+sintheta)/costheta)`

`=(cancel(sintheta +costheta)/(sinthetacostheta)) xx(costheta/cancel(costheta+sintheta))`

`=1/sintheta=csctheta=RHS`

Proved