Question

Question #09b84

Answer 1

Undefined.

Explanation:

`sin^-1(tan(pi/3))=sin^-1(sqrt3).`

Recall that,

`sin^-1x=theta, |x| le 1 iff sin theta=x, theta in [-pi/2,pi/2].`

Since, `sqrt3 cancelle 1, sin^-1(sqrt3), i.e., sin^-1(tan(pi/3))" is undefined."`