Question

Question #0654f

Answer 1

Given `costheta+sectheta=sqrt3`

`cos^3theta+sec^3theta`

`=(costheta+sectheta)^3-3costhetasectheta(costheta+sectheta)`

`=(sqrt3)^3-3costhetaxx1/costhetaxxsqrt3`

`=3sqrt3-3sqrt3=0`