Question

Question #c59d7

Answer 1

`-15 \ ms^(-1)`

Explanation:

Yes:

`h' = - 10t + 5`

In the previous question we established that contact with water occurs at `t = 2` by solving `−5t^2 + 5t + 10 = 0`.

And:

`h'(2) = -15 \ ms^(-1)`