Question

Question #8e17e

Answer 1

`(-12 sqrt 10)/49`

Explanation:

`sin x = 3/7`, then
`cos x = sqrt(7^2 - 3^2)/7 = sqrt 40/7 = (2sqrt10)/7`.
since it is in quadrant II, `cos x =( -2 sqrt10)/7`

`sin 2 x = 2sin x cos x`

`sin 2 x = 2(3/7)(( -2 sqrt10)/7) = (-12 sqrt 10)/49`