How do we prove that #(1 - tan theta)/(1 + tan theta) = (cot theta - 1)/(cot theta + 1)#?

1 Answer
Apr 5, 2017

Use #tantheta = sintheta/costheta# and #cottheta = costheta/sintheta#.

#(1 - sintheta/costheta)/(1 +sintheta/costheta) = (costheta/sintheta - 1)/(costheta/sintheta + 1)#

#((costheta - sin theta)/costheta)/((costheta+ sin theta)/costheta) = ((costheta - sin theta)/sintheta)/((costheta + sin theta)/sintheta)#

#(costheta - sin theta)/(costheta + sin theta) = (costheta - sin theta)/(costheta + sin theta)#

This is true for all values of #theta#, so we have proved this identity.

Hopefully this helps!