Question #515ea

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Answer 1 · 2017-04-08T18:51:42

#theta = 90^@# and #theta = 270^@#

Given: #sin^2(theta)cos(theta)=cos(theta)#

Subtract #cos(theta)# from both sides:

#sin^2(theta)cos(theta)-cos(theta)=0#

Factor:

#(sin^2(theta)-1)cos(theta)=0#

#sin^2(theta)-1= 0 and cos(theta)=0#

#sin^2(theta)=1 and cos(theta)=0#

#sin(theta)=+-1 and cos(theta)=0#

#sin(theta) = 1# at #90^@#

#sin(theta) = -1# at #270^@#

The same angles solve the #cos(theta)=0# equation