Question

Question #9e5bf

Answer 1

Please see the explanation

Explanation:

Given: `2sin^2(theta) =2+cos(2theta)`

Use the identity `1 -2sin^2(theta)=cos(2theta)`:

`2sin^2(theta) =2+1 -2sin^2(theta)`

Add `2sin^2(theta)` to both sides:

`4sin^2(theta) =3`

`sin^2(theta) = 3/4`

`sin(theta) = +-sqrt(3)/2`

From 0 to `2pi`

`theta = pi/3, (2pi)/3, (4pi)/3, and (5pi)/3`