Question

Simplify `cot(-x) sinx`?

Answer 1

`cot(-x) sinx -= -cos(x)`

Explanation:

We have:

`cot(-x) sinx -= cos(-x)/sin(-x) sinx`
`" " = cos(x)/(-sin(x)) sinx`
`" " = cos(x)/(-1)`
`" " = -cos(x)`