Question

An object with a mass of `125 g` is dropped into `750 mL` of water at `0^@C`. If the object cools by `70 ^@C` and the water warms by `3 ^@C`, what is the specific heat of the material that the object is made of?

Answer 1

`0.257` to 3 decimal places

Explanation:

Specific heat Capacity is a measurement of the amount of energy needed to change the temperature of 1 Kg of the material by `1^o`C.

The name given to this energy type is Joules and has the symbol `J`.

Known:
Specific heat of water is 1
`1ml" of water weighs "1g`

The relevant association is
`color(blue)("Mass "xx" change in temperature "xx" specific heat capacity")`

Let `x` be the Specific Heat Capacity of the object

For the object we have: `" "125g xx70^oC xx x`
For the water we have:`" "750xx3^oCxx1`

Giving:

`750xx3^oCxx1" " =" "J" "=" "125g xx70^oC xx x`

`=> x=(3xx750)/(125xx70)`

`0.257` to 3 decimal places