Question

For `f(t)=abs[t]+1`; how do you find f(-5),f(0) and f(-9)?

Answer 1

`f(-5) = 6`
`f(0) = 1`
`f(-9) = 10`

Explanation:

Given `f(t)=abs(t)+1`

For specific values of `t`:
`f(-5) = abs(-5)+1 = 5+1 = 6`

`f(0) = abs(0) + 1 = 0+1 = 1`

`f(-9) = abs(-9)+1 = 9+1 =10`