For #P(x)=3x^2-2x#; how do you find P(0),P(-2) and P(3)?

1 Answer
Jul 15, 2015

Given an equation defined with a variable place holder (in this case #x#), replace the variable place holder with specified value and evaluate to determine the value of the equation at that point.

Explanation:

If #P(color(red)(x)) = 3color(red)(x)^2-2color(red)(x)#

then

#P(color(red)(0)) = 3(color(red)(0))^2 - 2(color(red)(0)) = 0#

#P(color(red)(-2)) = 3(color(red)(-2))^2 -2(color(red)(-2)) = 12 +4 = 16#

#P(color(red)(3)) = 3(color(red)(3))^2-2(color(red)(3) )= 27-6 = 21#