Question

Given `f(x)=root3(x-8)` how do you find f(-208) and f(8)?

Answer 1

`f (- 208) = - 6`
`f (8) = 0`

Explanation:

To evaluate `f (x)` just substitute `x` in `f` expression...

`f (x) = root(3) {x - 8} rArr f (- 208) = root(3) {- 208 - 8} = root(3) {- 216} = root(3) {(- 6)^3} = - 6`

`f (x) = root(3) {x - 8} rArr f (8) = root(3) {8 - 8} = root(3) 0 = 0`