Given #f(x)=x+8, g(x)=x+8#, how do you find the values of x for which #f(x)/g(x)=32#?

1 Answer

As written, #f(x)/g(x)=1# for all values of #x# and there are no values where it will equal anything other than 1. I suspect that one of the functions was mistyped.

Explanation:

For #f(x)/g(x)# where #f(x)=x+8, g(x)=x+8#, we end up with:

#(x+8)/(x+8)=1# for all values of #x#. So there are no values of #x# where #f(x)/g(x)=32#.

I suspect that one of the functions was mistyped.