Question

Graph the function y=2/3x−1. I can't seem to remember how to do this. Can somebody refresh me plz?

Answer 1

See the explanation below!

Explanation:

Remember, two points are enough to draw a straight line in `xy-\text{plane}`.

So, just pick some radom value of `x` and put it in the equation to get the corresponding value of `y`. Just record this order pair and find another one just like this.

Then locate and graph these two points on the graph paper to connect the two points by a ruler. That's it!

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Put `x=0` in the equation and we will get:

`y=2/3(0)-1`

Simplify:

`y=-1`

The first point is `(0\ ,\ -1)`

Now simply put `y=0` to get:

`0={2x}/3-1`

Solve for `x` to get:

`x=3/2` `\ \ \`or `\ \ \` `x=1.5`

The second point is `(3/2\ ,\ 0)`

Just locate these two points on the graph and then connect them by a line to get: