How do you evaluate #(ab)^2# for #a=4# and #b=3#?

Question

11926 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-13T03:01:59

See a solution process below:

To evaluate the expression in the problem, substitute:

#color(red)(4)# for each occurrence of #color(red)(a)#

#color(blue)(3)# for each occurrence of #color(blue)(b)#

#(color(red)(a)color(blue)(b))^2# becomes:

#(color(red)(4) * color(blue)(3))^2 => (12)^2 => 144#

Or a dozen dozen.

Or a gross.