Question

How do you evaluate `(cos^3 (pi/6))(sin (pi/4))`?

Answer 1

from trigonometric table we know
`cos (pi/6)=sqrt3/2 and sin(pi/4)=1/sqrt2`
putting these values we get
given expression
`=(sqrt3/2)^3xx1/sqrt2=(3sqrt3)/(8sqrt2)`