How do you evaluate f(-2) given #f(x)=x^2-4#?

1 Answer
Jun 20, 2018

#0#

Explanation:

A function is a rule that tells you how you associate every input with its output.

This is what we mean when we write #y=f(x)#: we want to say that the #y# value depends on the #x# value, and the function #f# decides how this happen.

In your example, you have #y = x^2-4#, which means that whenever you choose an input #x#, you must square it (#x^2#) and subtract four (#x^2-4#) to get the output.

So, evaluating a function means exactly to do what I just said, but with a particular value chosen for #x#, in this case #-2#.

So, we only need to repeat the generic steps (square the input and subtract four), knowing that the input is #-2#.

When we square it we get #(-2)^2 = (-2)\times(-2) =4#, and when we subtract #4# we get #4-4=0#.

Once you get this concept, there is a faster way to evaluate functions: simply substitute the generic #x# value with the one you're interested in: we can rewrite the generic equation #x^2-4#, plugging #-2# where we see #x#. The equation becomes

#(-2)^2-4 = 4-4=0#