How do you evaluate #g(10)# given #g(x)=-3x+1#?
1 Answer
Feb 25, 2017
Explanation:
#"To evaluate g(10), substitute x=10 into g(x)"#
#rArrg(color(red)(10))=(-3xxcolor(red)(10))+1#
#color(white)(xxxxxx)=-30+1#
#color(white)(xxxxxx)=-29#
