Question

How do you evaluate `sec((2pi)/3)-tan((pi)/6)`?

Answer 1

`-(2 + sqrt3/3)`

Explanation:

Trig table -->
`sec ((2pi)/3) = 1/cos ((2pi)/3) = 1/(-1/2) = -2`
`tan (pi/6) = sqrt3/3`
Therefor,
`sec ((2pi)/3) - tan (pi/6) = - 2 - sqrt3/3`