How do you evaluate #sqrts+absr# given r=-3, s=4, t=-7?

2 Answers
Jun 3, 2018

See a solution process below:

Explanation:

The variable #t# is not use in the expression in the problem therefore we can ignore it in this problem.

To evaluate #sqrt(s) +abs(r)# we need to substitute:
- #color(red)(-3)# for each occurrence of #color(red)(r)#
- #color(blue)(4)# for each occurrence of #color(blue)(s)#

#sqrt(color(blue)(s)) + abs(color(red)(r))# becomes:

#sqrt(color(blue)(4)) + abs(color(red)(-3)) => 2 + 3 => 5#

Jun 3, 2018

#5#

Explanation:

#"substitute the given values into the expression"#

#sqrtcolor(red)(4)+|color(blue)(-3)|=2+3=5#

#"note that the absolute value always returns a positive"#
#"value"#