How do you evaluate the expression #(y-6)/(x-9)# when x=-3 and y=-2?

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Answer 1 · 2017-01-14T21:03:41

Substitute #-3# for #x# and #-2# for #y# into the expression and calculate the result. See the full explanation below:

Substitute #color(red)(-3)# for #color(red)(x)# and #color(blue)(-2)# for #color(blue)(y)# into the expression:

#(color(blue)(y) - 6)/(color(red)(x) - 9)# after substitution becomes:

#(color(blue)(-2) - 6)/(color(red)(-3) - 9)#

We can now calculate the value of the expression:

#(color(blue)(-2) - 6)/(color(red)(-3) - 9)#

#-8/-12#

#8/12#

#(4 xx 2)/(4 xx 3)#

#(color(red)(cancel(color(black)(4))) xx 2)/(color(red)(cancel(color(black)(4))) xx 3)#

#2/3#