How do you evaluate the function #f(x) = -1/3x+7# for #f(-6)#?
1 Answer
May 15, 2018
Explanation:
#"to evaluate "f(-6)" substitute "x=-6" into "f(x)#
#rArrf(color(red)(-6))=-1/cancel(3)^1xx-cancel(color(red)(6))^2+7#
#color(white)(rArrf(-6))=2+7=9#
