How do you evaluate the function #f(x) = 3x – 2#, when x = –1?

1 Answer
Jul 8, 2015

Replacing #x# with #(-1)# and performing standard arithmetic gives
#color(white)("XXXX")##f(-1) = -5#

Explanation:

If #f(x) = 3x-2#

when the variable #x# is replace with an actual value #(-1)#
we get
#color(white)("XXXX")##f(-1) = 3(-1) -2#
#color(white)("XXXX")##color(white)("XXXX")##=-3-2#
#color(white)("XXXX")##color(white)("XXXX")##=-5#