Question

How do you evaluate the function `h(x)=-x^2+10` when x=3?

Answer 1

`h(3)=1`

Explanation:

If `h(color(blue)x)=-color(blue)x^2+10`
then
`color(white)("XX")h(color(blue)3)=-color(blue)(""(3))^2+10`
`color(white)("XXXxx")=-9+10`
`color(white)("XXXxx")=1`