How do you find #g(1)# given #g(a)=3^(3a-2)#?

1 Answer
smendyka
Apr 17, 2017

See the entire solution process below:

Explanation:

To find #g(1)# substitute #color(red)(1)# for each occurrence of #a# in the function #g(a)#:

#g(color(red)(a)) = 3^(3color(red)(a) - 2)# becomes:

#g(color(red)(1)) = 3^((3 * color(red)(1)) - 2)#

#g(color(red)(1)) = 3^(3 - 2)#

#g(color(red)(1)) = 3^1#

#g(color(red)(1)) = 3#

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