How do you find #g(h(24))# given #f(x)=2x-1# and #g(x)=3x# and #h(x)=x^2+1#?
1 Answer
Mar 6, 2017
Explanation:
Evaluate g(h(24)) by first evaluating h(24)
#rArrh(color(red)(24))=(color(red)(24))^2+1#
#color(white)(rAerrh(24))=576+1#
#color(white)(rArrh(24)xx)=577# Now substitute this value into g(x)
#rArrg(h(24))=g(577)#
#=3xx577#
#=1731#
