How do you find #g(t/4)# given #g(t)=t+3#?
1 Answer
Aug 5, 2016
Explanation:
To evaluate
#g(t/4) #
#color(blue)"substitute t=t/4 into g(t)"#
#rArrg(color(red)(t/4))=color(red)(t/4)+3# We can express
#t/4+3" as a single fraction"#
#rArrt/4+(3/1xx 4/4)=t/4+12/4# we now have a common denominator and can add the numerators.
#rArrg(t/4)=(t+12)/4#
