Question

How do you find `(h-g)(n)` given `h(n)=4n+5` and `g(n)=3n+4`?

Answer 1

`(h-g)(n)=n+1`

Explanation:

To find the new function all you have to do is apply the operation in the order that is specified. In this case, subtract the two functions:

`(h-g)(n)=h(n)-g(n)`

`rArr(h-g)(n)=[4n+5]-[3n+4]`

`rArr(h-g)(n)=(4n-3n)+(5-4)=n+1`