Question

How do you find the exact value of `arccos(cos(-5pi))`?

Answer 1

`15°42'` 28.6"#

Explanation:

`arccos(cos(-5pi))`

`=arccos(cos(-15.70796327)`

`=arccos(cos-15.70796327)`

`=arccos(0.962654127)`

`=15.70796327`

`=15°42'` 28.6"