How do you find the exact value of #sin2theta+2sintheta=0# in the interval #0<=theta<360#?

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Answer 1 · 2016-12-17T16:23:52

#theta# = 0 and 180 degree

#sin 2 theta + 2 sin theta = 0#

or, # 2sin theta cos theta + 2 sin theta = 0#

or, #2 sin theta(cos theta + 1) = 0#

or, #2sin theta = 0, (cos theta + 1) = 0#

or, #sin theta = 0 and cos theta = -1#

or, #theta = o cos theta = cos 180 degree#

or, # theta# = 0 and 180 degree [ which is in the interval of # 0<=theta < 360#