Question

How do you find the solution to `4(cottheta+1)=2(cottheta+2)` if `0<=theta<2pi`?

Answer 1

`pi/2, (3 pi )/2`

Explanation:

`4(cottheta+1)=2(cottheta+2)`

`4 cottheta+ 4 - 2 cottheta- 4 =0`

`cottheta =0`

`implies theta = (2n + 1)/2 pi, n in \Z`

for `theta in [0, 2 pi)`

that means: `pi/2, (3 pi )/2`