How do you find the solution to #4sintheta-1=2sintheta+1# if #0<=theta<360#?

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Answer 1 · 2017-01-09T05:38:45

#90^@#

4sin t - 1 = 2sin t + 1
2sin t = 2
sin t = 1
Trig unit circle --> #t = pi/2 or 90^@#
General answer:
#t = pi/2 + 2kpi#

Answer 2 · 2017-01-09T05:41:56

The solutins are #S={30º,150º}#

#4sin theta-1=2sin theta#

#4sintheta-1-color(red)(2sin theta)=2sin theta-color(red)(2sin theta)#

#2sin theta-1=0#

#2sintheta=1#

#sin theta=1/2#

#theta=30º#,

#theta=150º#