Question

How do you find `w(2)` given `w(x)=4x-1`?

Answer 1

See the entire solution process below:

Explanation:

To solve this we must substitute `color(red)(2)` for every occurrence of `color(red)(x)` in the function:

`w(color(red)(x)) = 4color(red)(x) - 1` becomes:

`w(color(red)(2)) = (4 xx color(red)(2)) - 1`

`w(color(red)(2)) = 8 - 1`

`w(color(red)(2)) = 7`